001

De stroom door de condensator is:

a   7.5 mA
b   10 mA
c   2.5 mA
d   12.5 mA

Ir = U/R = 60/6KΩ = 10mA

It   = √ [10 x 10]mA  +[Ic x Ic]

[It x It ] =  [10 x 10] + [Ic x Ic]

[12.5 x 12.5] = [10 x 10] + [Ic x Ic]

156  = 100 +  [Ic x Ic]

56 = [Ic x Ic]

Ic = √56 = 7.5 mA

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