001

De stroom door de condensator is:

a   7.5 mA
b   10 mA
c   2.5 mA
d   12.5 mA

Ir = U/R = 60/6KΩ = 10mA

It =√ [10*10]mA+[Ic*Ic]

[It*It] = [10*10] + [Ic*Ic]
[12.5*12.5] = [10*10] + [Ic*Ic]
156 = 100 + [Ic*Ic]
56 = [Ic*Ic]
Ic = √56 = 7.5 mA

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